Need help about ui function

[jmv38]

@omz i've got an error : no objectiveC MPMediaPickerController blabla... Is this ios10 only?
btw, would be nice to be able to copy the error messages.

[dgelessus]

@jmv38 It works on iOS 9 too. For some reason, MediaPlayer.framework (where MPMediaPickerController is from) is loaded by default on iOS 10, but on iOS 9 you first need to load it manually:

NSBundle.bundleWithPath_("/System/Library/Frameworks/MediaPlayer.framework").load()
MPicker = ObjCClass("MPMediaPickerController")

By the way, it is possible to copy error messages. When you open the traceback navigator (the red window that pops up when an exception happens) there is a "Print Traceback" option at the top of the traceback list. This prints a normal Python traceback to the console, which you can copy and paste like normal.

[jmv38]

thank you @dgelessus .
I dont have the print option, it must be a pythonista3 feature.

[lukaskollmer]

@omz doesn't iOS 10 require a NSAppleMusicUsageDescription entry in the Info.plist to access the MediaPlayer framework?

[omz]

@lukaskollmer Only if the app is linked against the iOS 10 SDK. The current App Store versions are linked against the iOS 9 SDK, and the betas do have that Info.plist key.

[wolf71]

@Phuket2 Thanks.

error:

Traceback (most recent call last):
File "/private/var/mobile/Containers/Shared/AppGroup/A393CF34-1371-47E1-B49E-D9AF34A644DC/Pythonista3/Documents/Test/test1.py", line 41, in <module>
mc = MYUIClass(ui_file, frame=f, bg_color='white')
File "/private/var/mobile/Containers/Shared/AppGroup/A393CF34-1371-47E1-B49E-D9AF34A644DC/Pythonista3/Documents/Test/test1.py", line 20, in init
super().init(*args, **kwargs)
TypeError: super() takes at least 1 argument (0 given)

[Phuket2]

@wolf71 , are you using Pythonista 2?

[Phuket2]

@wolf71 , well I guess you are. If you replace the super().xxx line as the below it will work.

class MYUIClass(ui.View):
    def __init__(self, ui_file, *args, **kwargs):
        ui.load_view(ui_file, pyui_bindings(self))
        #super().__init__(*args, **kwargs)
        ui.View.__init__(self, *args, **kwargs)

[wolf71]

@Phuket2 said:

ui.View.init(self, *args, **kwargs)

1. Python 2.7
2. ui.View.init(self, *args, **kwargs) work.
3. Thank you very much. :-)

[Phuket2]

@wolf71 , great. The call to super is a Python 3 construct. But it's nice, because it's generic. It just calls the base class without having to refer to it absolutely. In the Python 2 version, you can see calling ui.View.init() by name. It may seem like a small difference, but it really can make life a lot easier if you chop,and change your code object model. I am just thinking about small things here. But on a medium to large project I am sure it can have a profound impact. I can only speculate as I have never done a large project in Python.

My comments above are about when you are inheriting from just one base class. You have to think a little harder(aka, have more understanding) if your are inheriting from multiple base classes (multiple inheritance).