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Prime number finder

I have some python prime number code which finds out prime numbers. I was looking for a way to make it more efficient as this currently checks for all factors until it reachers the number, it possible could you make the explainations simple as I am 13. Here is the code:
import time print('Made by Yasas Kulatunga, Dhari Prashanth and Dhivy Prashanth') print(' ') number = int(input("Enter a Number: ")) print(' ') time.sleep(0.5) print('THINKING.') time.sleep(0.5) print('THINKING..') time.sleep(0.5) print('THINKING...') time.sleep(0.5) print(' ') c = 0 while number: for i in range(2,number): if number % i == 0: print(str(i),"times",str(number//i),"is",str(number)) time.sleep(0.3) c = c + 1 if c == 0: print(' ') print(str(number),"has no factors apart from 1 and itself, therefore it is a prime number") print(' ') time.sleep(0.3) else: print(' ') print(str(number),"is not a prime number, the number has factors more than 1 and the number itself.") print(' ') time.sleep(0.3) number = int(input('Enter a number: ')) print(' ') time.sleep(0.3) c = 0

I never used a for / else loop before but here it works well. When we find the first factor, we print a not prime message and then fast fail out of the loop with break. If the loop finishes without a break then we use the else clause to tell the use that we have a prime number.
Let's call this the 5F approach: finding first factor fast fail...
import time print('Made by Yasas Kulatunga, Dhari Prashanth and Dhivy Prashanth') print(' ') number = int(input("Enter a Number: ").strip()) print(' ') time.sleep(0.5) print('THINKING.') time.sleep(0.5) print('THINKING..') time.sleep(0.5) print('THINKING...') time.sleep(0.5) print(' ') while number: for i in range(2, number): if number % i == 0: print('{} is not prime.'.format(number)) break else: print('{} is prime!'.format(number)) number = int(input("Enter a Number: ").strip())

More efficient way would be to check the number for divisibility, only till its' square root  1.
Because the largest factor of any number cannot exceed it's square root, there is no need for range to go beyond that.
With minimal alteration to script given by @ccc , this would be more efficient.# Revised as per bug reported by @cvp # This code takes care of numbers 1 and 2 also. import time from math import sqrt print('Made by Yasas Kulatunga, Dhari Prashanth and Dhivy Prashanth') print(' ') number = int(input("Enter a Number: ").strip()) maxfact = int(sqrt(number)+1) print(' ') time.sleep(0.5) print('THINKING.') time.sleep(0.5) print('THINKING..') time.sleep(0.5) print('THINKING...') time.sleep(0.5) print(' ') while number: for i in range(2, maxfact): if number % i == 0: print('{} is not prime.'.format(number)) break else: print('{} is prime!'.format(number)) number = int(input("Enter a Number: ").strip()) maxfact = int(sqrt(number)+1)

The above implementations do not deal with the fact that all values less than 2 are not prime.
https://primes.utm.edu/notes/faq/one.html
https://www.reference.com/math/0primenumber1964bd6272594f3f
https://primes.utm.edu/notes/faq/negative_primes.html 
Bug, try with 25
maxfact = int(sqrt(number)1) > maxfact = int(sqrt(number))

Bug, try with 25
for i in range(2, maxfact+1):

Check if 2 is a divisor but skip all other even divisors
(Perhaps what @ccc minded with "less than 2")for i in [2]+list(range(3, maxfact+1,2)):

The exact output is this, although it is from the original code I posted on top: Enter a Number: 25
THINKING.
THINKING..
THINKING...5 times 5 is 25
25 is not a prime number, the number has factors more than 1 and the number itself.
Enter a number:

Sorry, I had tested the last code of @ramvee until √  1

But he was almost right, you have to check only until sqrt(number),
And, what I just added, by skipping the even divisors!For instance, if number is 29, your code checks the division by
2 3 4 5 6 7 8 9 10 11 12 13 ...29
But "mine" (& @ramvee) only
2 3 5 
@cvp, If you go the the three vertical dots at the upper right of your forum post, you can edit it to add new insights. This is probably a better approach than replying to your own posts.

@ccc, Thanks, I knew it but sometimes I forget it, and sometimes I'm not sure how other people see an update, while I'm sure they see a new response

@cvp
Thank you for pointing the bug in my code. :)I put in your line of code
for i in [2]+list(range(3, maxfact+1,2)):
and it works fine,
Except it shows 2 is not a prime.. If we sort this we're good.. I think.. 
I think the consecutive 3 post's from @cvp might have been better done in edit. Maybe and maybe not. If the items inside a post themselves were also threaded , then it would be clear to do like that. But they are not. Just saying it's not a clear cut choice.


@cvp , lol, yes he is normally right. But need to keep him on his toes. 😱😈