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    This is the community forum for my apps Pythonista and Editorial.

    For individual support questions, you can also send an email. If you have a very short question or just want to say hello — I'm @olemoritz on Twitter.


    [Feature Request] Password to lock Pythonista App for Parental Control

    Pythonista
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    • henryaukc
      henryaukc last edited by

      @Phuket2 @jonbThanks a lot! I will search about the hashlib thing. I agree the OpenDNS is a better solution but I just want give a more easier solutions to less technical parents to do it themselves.

      1 Reply Last reply Reply Quote 0
      • JonB
        JonB last edited by

        ok, I totally misread your original question -- these are your students, not your own kids!

        The Restrictions menu in the settings app lets you filter websites. This does turn out to restrict access in a webview inside pythonista as well (anything based on a WebView). You can provide either a "whitelist", or blacklist based in what Apple thinks is adult, or provide your own list.

        Now, the restrictions do not apply to urllib/requests or the like. so a kid could in theory make their own "browser" from scratch. That sort of kid will figure out a way around whatever restriction you put in place, and probably gas his own computer/phone at home anyway...

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        • henryaukc
          henryaukc last edited by

          I try to write an authentication script and put it in 'site-packages' as pythonista_startup.py. But it is easily by-passed even I typed the wrong password, it gave me some time to press the stop button for the script in-between the validating process. Seems like this is not a possible method to lock the pythonista environment with password.

          from passlib.hash import pbkdf2_sha256
          import dialogs
          import os
          
          file = './.passwd'
          
          if not os.path.isfile(file):
          	p1 = None
          	p2 = 'password'
          
          	while p1 != p2:
          		p1 = dialogs.password_alert('Create a password:\nPleaes enter your password', hide_cancel_button=True)
          		
          		if len(p1) == 0:
          			dialogs.hud_alert('Password can\'t be empty!')
          			continue
          		p2 = dialogs.password_alert('Pleaes enter your password again to confirm', hide_cancel_button=True)
          	
          		if p1 != p2:
          			dialogs.hud_alert('The password you entered does not match. Try again')	
          		
          	hash = pbkdf2_sha256.encrypt(p1, rounds=200000, salt_size=16)
          	
          	with open(file, 'w+') as F:
          		F.write(hash)
          		
          	if os.path.isfile(file) and os.path.getsize(file) > 0:
          		dialogs.hud_alert('Your password has been saved successfully!')	
          	else:
          		dialogs.hud_alert('Error! Password has not been saved!')
          else:
          	p1 = None
          	trial = 0
          	success = False
          	
          	while not success: 
          		p1 = dialogs.password_alert('Pleaes enter your password', hide_cancel_button=True)
          		with open(file, 'r') as F:
          			hash = F.read()
          		success = pbkdf2_sha256.verify(p1, hash)
          		if success:
          			dialogs.hud_alert('Login Success!')
          		else:
          			dialogs.hud_alert('Login Failed! Try again!')
          			trial += 1
          
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          • henryaukc
            henryaukc last edited by

            Any method can be called to quit Pythonista if too many failed attempt?

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            • JonB
              JonB last edited by

              you should be able to wrap the script in a try/except KeyboardInterrupt and then force quit if a KeyboardInterrupt happens.
              you can use

              import objc_util
              ObjCInstance(1)
              

              to force a crash.

              Alternatively, we could use objc to remove the X button.

              henryaukc 1 Reply Last reply Reply Quote 0
              • henryaukc
                henryaukc last edited by

                @jonB really? We can even remove that 'X' button? That's so powerful... Can we just stop responding to the touch events outside the dialog box? Then no one can stop the script or modify any codes when running the login script.

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                • dgelessus
                  dgelessus last edited by

                  os.abort() is the "safer" way to force-quit Pythonista, by the way. It should be somewhat cleaner than os._exit(0) or accessing bad memory at least.

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                  • henryaukc
                    henryaukc last edited by

                    Thanks. I am thinking to open a full-screen window so that the user can't press the stop script button or modify the scripts...

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                    • henryaukc
                      henryaukc @JonB last edited by

                      @JonB Hi, may I know how to use objc to remove the X button?

                      cvp 1 Reply Last reply Reply Quote 0
                      • ccc
                        ccc last edited by

                        https://omz-software.com/pythonista/docs/ios/ui.html#ui.View.present View.present(hide_close_button=True)

                        cvp 1 Reply Last reply Reply Quote 0
                        • cvp
                          cvp @ccc last edited by

                          @ccc I guess he wants to hide, not the close button, but the start/stop button for a non fullscreen script.

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                          • cvp
                            cvp @henryaukc last edited by cvp

                            @henryaukc said

                            how to use objc to remove the X button?

                            Please, for the fun, try this script and you will see the start/stop button disappear

                            from objc_util import *
                            import ui
                            
                            w=ObjCClass('UIApplication').sharedApplication().keyWindow()
                            main_view=w.rootViewController().view()
                            
                            def get_toolbar(view, indent):
                            	#get main editor toolbar, by recursively walking the view
                            	sv=view.subviews()
                            	for v in sv:
                            		#print(indent,v._get_objc_classname())
                            		if 'UIImageView' in str(v._get_objc_classname()):  
                            			# <UIImage:0x281108240 named(main: Stop2) {28, 28}>
                            			#print(v.image())
                            			o = v.image()
                            			if o:
                            				with ui.ImageContext(32,32) as ctx:
                            					o.drawAtPoint_(CGPoint(0,0))
                            					ui_image = ctx.get_image()					
                            					#ui_image.show()
                            					#print()
                            				if 'Stop2' in str(o):
                            					#print('+'*40)
                            					OMBarButton = v.superview().superview()
                            					OMBarButton.removeFromSuperview()
                            		tb= get_toolbar(v, indent+'  ')
                            get_toolbar(main_view, '')
                            

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