# Find consecutive elements in a list browsing

• posted
0

Trying to return True if there are duplicate items in a list.
Not working with numbers, and want to allow the user to make a list as long as they want...suggestions?

``````user = input("What's on your list??: ")
def has_consecutive():
items = user.split() #trying to split list into items to compare
if (items[0] == items[+1]): #trying to compare one item to the next to find duplicates
return True #return true if duplicates are found

else:
return False #return False if no duplicates are found

has_consecutive()`````````

• posted
0

@craigmrock try this

``````def has_duplicate():
user = '1 2 3 4 2'
items = user.split()
for i in range(0,len(items)-1): # loop on items except last one
if items[i] in items[i+1:]:     # check of i-th item exists in next ones
return True
return False
print(has_duplicate())
``````

Checks if duplicates exist but not only consecutive...

``````        if items[i] == items[i+1]:      # check if i-th item is equal to next one
``````

Will check consecutive duplicates

• posted
1

``````def hasdupelems(l):
return len(l) != len(set(l))

print(hasdupelems(['ab', 'cd', 'ab', 'ef']))
print(hasdupelems(['ab', 'cd',  'ef']))
``````

Internal error.

Oops! Looks like something went wrong!