Optimising the UI for a 2048 Widget Game

JonB

oh wait, this is a scene game? Im surprised that works at all in the the widget. I though you were just using views?

All of those dels should be unnecessary, since unreferenced items should automatically be deleted at the end of the scope where it is declared. but gc.collect() might help?

ccc

Optimizing in a different place... A dict will speed up printGrid().

bg_colors = {2: "#fbffaa",
             4: "#fff1aa",
             8: "#ffb86a",
             16: "#ff703e",
             32: "#ff4f4f",
             64: "#f20000",
             128: "#edf800",
             256: "#7cff61",
             512: "#00f315",
             1024: "#23ffe2",
             2048: "#47b7ff",
             4096: "#0b20ff",
             8192: "#9400db"}


def printGrid():
    """Outputs the current grid onto the UI, along with score, and number of moves"""
    for y in range(4):
        for x in range(4):
            value = playGrid[y][x]
            tile = screen["tile{}{}".format(y, x)]
            tile.text = "" if value == 0 else str(value)
            tile.font = ("<system-bold>", 42 if value == 0 else 50)
            tile.background_color = bg_colors.get(value, "#000000")
            tile.text_color = "#000000" if 0 < value < 4096 else "#ffffff"
            del tile         
    screen["scoreLabel"].text = "Score: " + str(score)
    screen["movesLabel"].text = "Moves: " + str(moves)

ccc

You could also make all four buttons share a single action...

def button_pressed(sender)
    moveTilesDirection('up right down left'.split().index(sender.text))
    if not failed:
        generateNewNumbers()
        printGrid()

Buzzerb

@ccc Speed isn’t really the problem as far as I know, but it’s possible that your method helps, I’ll test it. And thank you for the all buttons sharing a single action script.

Buzzerb

@JonB I’m not sure what would classify this as a scene game, could you explain?

Edit: @ccc In that case I'm not using a scene game

ccc

Also tryout f”strings” like:

    screen[f"tile{y}{x}"]         
    screen["scoreLabel"].text = f"Score: {score}"
    screen["movesLabel"].text = f"Moves: {moves}"

ccc

Scene games are built using http://omz-software.com/pythonista/docs/ios/scene.html

Buzzerb

@ccc Not sure how legitimate it is but I read that '+' string concatenation is faster when only combining two strings, and f string is faster with more. Also, is using dict.get with a default significantly slower or faster than just fetching a value because my game is unlikely to get above 8192, and I could always add more pairs to the dictionary.

ccc

https://docs.python.org/3/library/timeit.html#timeit.timeit will give you a good sense of performance differences. My bet is that timeit.timeit() will reveal that the dict will be faster then the repeated if/else. However the reason that I suggested the dict approach for a widget is code size.

Also try timeit() on the string question but remember that the current code is not concatenating two strings. That innocent little call to str() effects performance as well. Let timeit() guide choices that really matter to you.

https://goo.gl/images/BNdGdm

Buzzerb

@ccc I looked into using timeit to determine performance of all these changes but ultimately decided that performance was almost definitely not the problem my widget was encountering.

Thank you for the dictionary approach anyway, it’s much more concise than I would’ve managed