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    Welcome!

    This is the community forum for my apps Pythonista and Editorial.

    For individual support questions, you can also send an email. If you have a very short question or just want to say hello — I'm @olemoritz on Twitter.


    Equally spaced circle in UI

    Pythonista
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    • cvp
      cvp @AZOM last edited by cvp

      @AZOM if you go here, you can download the zip in your iCloud Drive, unzip it and copy the py to Pythonista
      Via split view

      AZOM pavlinb 2 Replies Last reply Reply Quote 0
      • AZOM
        AZOM @cvp last edited by

        @cvp
        Thank you a lot, it’s working :)

        mikael 1 Reply Last reply Reply Quote 0
        • mikael
          mikael @AZOM last edited by

          @AZOM, also, if you install stash, you can just wget a file from a url.

          1 Reply Last reply Reply Quote 0
          • pavlinb
            pavlinb @cvp last edited by pavlinb

            @cvp Is it possible on iPhone (split view)?

            cvp 2 Replies Last reply Reply Quote 0
            • cvp
              cvp @pavlinb last edited by

              @pavlinb Sorry but I don't know. I have a very old iPhone 5s not allowed for iOS 13 nor iPadOS

              1 Reply Last reply Reply Quote 0
              • cvp
                cvp @pavlinb last edited by

                @pavlinb it seems that does it exist on iPhone but hoped on iOS 14.
                It is ok on my iPad mini 4 and it is not very bigger than the biggest iPhone

                mikael 1 Reply Last reply Reply Quote 0
                • mikael
                  mikael @cvp last edited by

                  @cvp, you can open and unzip a zip in Pythonista.

                  cvp 1 Reply Last reply Reply Quote 0
                  • cvp
                    cvp @mikael last edited by cvp

                    @mikael sure. It was only to show that you can download a file (zip or not) from GitHub without needing a Pythonista script to import it, via iCloud then split view.
                    I know there are several ways.
                    We are not yet using a lot download to Files, then drag and drop to another app, like Pythonista

                    Personally, I use my script

                    1 Reply Last reply Reply Quote 0
                    • AZOM
                      AZOM @mikael last edited by

                      @mikael
                      How do I change the circle’s position (horizontally) with your code that you first gave me?

                      mikael 1 Reply Last reply Reply Quote 0
                      • mikael
                        mikael @AZOM last edited by mikael

                        @AZOM, GridView has a pack_x argument:

                        g = GridView(
                            count_x=1,
                            pack_x=GridView.START)
                        

                        Using END instead would move them to the right edge.

                        You can also control the placement down to the pixel by providing an additional gap argument, which in this case is essentially the distance to the edge.

                        See the end of this page for the documentation.

                        AZOM 1 Reply Last reply Reply Quote 1
                        • AZOM
                          AZOM @mikael last edited by

                          @mikael
                          Yeah, thanks for all.

                          1 Reply Last reply Reply Quote 0
                          • mikael
                            mikael @Guest last edited by mikael

                            @adomanim, here you go. You need the vector.py from here.

                            import ui
                            import vector
                            
                            chars = 'ABCDEFGH'
                            start_angle = 0 # First character on the right
                            
                            circle_color = 'red'
                            char_color = 'white'
                            char_font = ('Apple SD Gothic Neo', 32)
                            
                            diameter = min(ui.get_screen_size())/2
                            
                            root = ui.View()
                            root.present()
                            
                            pointer = vector.Vector()
                            pointer.magnitude = diameter/2
                            pointer.degrees = start_angle
                            
                            for c in chars:
                                label = ui.Label(
                                    text=c,
                                    text_color=char_color,
                                    alignment=ui.ALIGN_CENTER,
                                    font=char_font)
                                label.center = root.bounds.center() + tuple(pointer)
                                pointer.degrees += 360/len(chars)
                                root.add_subview(label)
                                
                                
                            class CircleView(ui.View):
                                
                                def layout(self):
                                    self.corner_radius = self.width/2
                                    
                            circle = CircleView(
                                width=diameter, height=diameter,
                                border_width=1, border_color=circle_color,
                                center = root.bounds.center()
                            )
                            
                            root.add_subview(circle)
                            circle.send_to_back()
                            
                            1 Reply Last reply Reply Quote 0
                            • AZOM
                              AZOM last edited by

                              This is for my friend: can someone make a 3 points generator on the circumference of a circle that has a diameter of 2 units. And with these three x, y coordinates, look if the point (0,5:0) is in the triangle made with the three points?

                              mikael 1 Reply Last reply Reply Quote 0
                              • mikael
                                mikael @AZOM last edited by

                                @AZOM, sounds like a school exercise. Wouldn’t it be more useful for your friend to spend the time on cracking it?

                                AZOM 2 Replies Last reply Reply Quote 0
                                • AZOM
                                  AZOM @mikael last edited by AZOM

                                  @mikael

                                  No, we are in high school, and this is not a homework or something like that, he just like maths and wants help to “verify” his answer to a question he gets somewhere on the web.

                                  1 Reply Last reply Reply Quote 0
                                  • AZOM
                                    AZOM @mikael last edited by AZOM

                                    @mikael

                                    The only thing I am doing wrong is with rounding up numbers (I think it is my only problem) beau a se if 2 values that I compare are like at 0,000001 appart, they are not equal. Also, I am using cos and sin to try to find the three points. And my friend doesn’t program btw.

                                    mikael 2 Replies Last reply Reply Quote 0
                                    • mikael
                                      mikael @AZOM last edited by

                                      @AZOM, try

                                      0.1 + 0.2 == 0.3
                                      

                                      If you are not satisfied with the result, you might try to use the Decimal class, where you can also

                                      getcontext().prec == 6
                                      
                                      1 Reply Last reply Reply Quote 0
                                      • mikael
                                        mikael @AZOM last edited by

                                        @AZOM, meanwhile, for your problem, I would use ui.Path with the three points, then hit_test with the given point. I do not know whether this would be any more accurate than the method you are using, though.

                                        AZOM 1 Reply Last reply Reply Quote 1
                                        • AZOM
                                          AZOM @mikael last edited by

                                          @mikael

                                          Right, now, I don’t have my program, but I’m going to send it at ~5h pm.

                                          mikael 1 Reply Last reply Reply Quote 0
                                          • mikael
                                            mikael @AZOM last edited by

                                            @AZOM, going to get my beauty sleep now, but here’s what I meant by the hit test:

                                            import random
                                            import ui
                                            import vector
                                            
                                            random_angle = lambda: random.random() * 360
                                            
                                            p = ui.Path()
                                            point = vector.Vector(0, 1)
                                            
                                            point.degrees = random_angle()
                                            p.move_to(*point)
                                            print(point)
                                            for _ in range(2):
                                                point.degrees = random_angle()
                                                p.line_to(*point)
                                                print(point)
                                            p.close()
                                                
                                            print('IN' if p.hit_test(0.5,0) else 'OUT') 
                                            
                                            1 Reply Last reply Reply Quote 1
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