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    'for loop' exit at first passage

    Pythonista
    for loop error
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    • mibradoc
      mibradoc last edited by

      here is full code :
      https://www.dropbox.com/sh/puqht9zcmjfrzsh/AAA1_zJt1Kt0YFU3avW2dHeja?dl=0

      stephen cvp 3 Replies Last reply Reply Quote 0
      • stephen
        stephen @mibradoc last edited by stephen

        UPDATED

        @mibradoc output:

        
        grille à résoudre ? libre
        
        [[1 4 0 0 7 0 9 2 0]
         [3 0 0 0 0 2 8 5 4]
         [0 0 0 0 5 0 6 0 7]
         [0 0 0 2 0 0 0 7 0]
         [9 0 6 0 0 0 4 0 1]
         [0 5 0 0 0 6 0 0 0]
         [0 0 9 0 6 0 0 0 0]
         [5 3 0 7 0 0 0 0 8]
         [0 8 0 0 2 0 0 3 9]]
        50
        (1, 1) [3, 4] 2
        0
        1
        2
        (3, 2) [3, 5] 0
        0
        1
        2
        (5, 4) [3, 5] 3
        3
        4
        5
        (7, 5) [0, 2] 4
        3
        4
        5
        (9, 3) [4, 5] 5
        3
        4
        5
        (3, 4) [3, 4] 3
        3
        4
        5
        (8, 0) [3, 5] 2
        0
        1
        2
        (8, 0) [3, 5] 2
        0
        1
        2
        
        [[1 4 3 0 7 0 9 2 3]
         [3 0 0 0 0 2 8 5 4]
         [0 0 0 0 5 0 6 1 7]
         [0 0 5 2 3 5 3 7 0]
         [9 7 6 0 0 7 4 0 1]
         [0 5 0 0 0 6 0 9 0]
         [0 0 9 0 6 0 0 0 0]
         [5 3 0 7 0 0 0 0 8]
         [0 8 0 0 2 0 0 3 9]]
        40
        3
        
        
        cvp 1 Reply Last reply Reply Quote 0
        • cvp
          cvp @mibradoc last edited by

          @mibradoc run gives an error

          grille à résoudre ? libre
          
          [[1 4 0 0 7 0 9 2 0]
           [3 0 0 0 0 2 8 5 4]
           [0 0 0 0 5 0 6 0 7]
           [0 0 0 2 0 0 0 7 0]
           [9 0 6 0 0 0 4 0 1]
           [0 5 0 0 0 6 0 0 0]
           [0 0 9 0 6 0 0 0 0]
           [5 3 0 7 0 0 0 0 8]
           [0 8 0 0 2 0 0 3 9]]
          50
          (1, 1) [3, 4] 2
          0
          Traceback (most recent call last):
            File "/private/var/mobile/Containers/Shared/AppGroup/668A7D98-7216-47ED-917D-AA0B6173167E/Pythonista3/Documents/aa.py", line 147, in <module>
              for colonne in range((numero_carre_sans_chiffre % 3)*3,(numero_carre_sans_chiffre % 3)*3 + 3) :
          NameError: name 'numero_carre_sans_chiffre' is not defined
          
          1 Reply Last reply Reply Quote 0
          • cvp
            cvp @stephen last edited by

            @stephen did you change code?

            stephen 1 Reply Last reply Reply Quote 0
            • cvp
              cvp @mibradoc last edited by

              @mibradoc you say
              "The for loop is line # 141
              using breakpoint you 'll see the jump to line 147 after the first print "

              but line 147 is still in the loop, due to its indentation

              1 Reply Last reply Reply Quote 0
              • stephen
                stephen @cvp last edited by

                @cvp yes im sorry, didnt realize it didnt paste in

                I CHANGED:

                • for colonne in range((numero_carre % 3)*3,(numero_carre % 3)*3 + 3) :
                • #colonnes_possibles=[] ⇒ colonnes_possibles=[]

                not sure what expected outcome isnexpected tho

                for numero_carre in range ( (numcarre_altex // 3) * 3,((numcarre_altex//3)*3) + 3 ) :
                				print (numero_carre) # BUG !!  sortie de la boucle for après le 1er passage !! 
                				#if numero_carre != numcarre_altex and key[0] not in carrint(numero_carre) :
                					#numero_carre_sans_chiffre = numero_carre
                					
                				colonnes_possibles=[]
                				for colonne in range((numero_carre % 3)*3,(numero_carre % 3)*3 + 3) :
                						if puzzle[ ligne_a_analyser , colonne ] == 0 and key[0] not in puzzle[:9,colonne]:
                							colonnes_possibles.append(colonne)
                				if len(colonnes_possibles)	== 1 :
                					fn_remplir_case ( ligne_a_analyser , colonnes_possibles[0] , key[0] )
                						#print()
                						#print (puzzle)
                						#print ()
                
                
                cvp 1 Reply Last reply Reply Quote 0
                • cvp
                  cvp @stephen last edited by

                  @stephen understood, we will wait on réaction about my last post.

                  1 Reply Last reply Reply Quote 1
                  • stephen
                    stephen last edited by

                    @cvp this feels more like what hes probably looking for? comented out print (numero_carre)
                    on line 143

                    grille à résoudre ? libre
                    
                    [[1 4 0 0 7 0 9 2 0]
                     [3 0 0 0 0 2 8 5 4]
                     [0 0 0 0 5 0 6 0 7]
                     [0 0 0 2 0 0 0 7 0]
                     [9 0 6 0 0 0 4 0 1]
                     [0 5 0 0 0 6 0 0 0]
                     [0 0 9 0 6 0 0 0 0]
                     [5 3 0 7 0 0 0 0 8]
                     [0 8 0 0 2 0 0 3 9]]
                    50
                    (1, 1) [3, 4] 2
                    (3, 2) [3, 5] 0
                    (5, 4) [3, 5] 3
                    (7, 5) [0, 2] 4
                    (9, 3) [4, 5] 5
                    (3, 4) [3, 4] 3
                    (8, 0) [3, 5] 2
                    (8, 0) [3, 5] 2
                    
                    [[1 4 3 0 7 0 9 2 3]
                     [3 0 0 0 0 2 8 5 4]
                     [0 0 0 0 5 0 6 1 7]
                     [0 0 5 2 3 5 3 7 0]
                     [9 7 6 0 0 7 4 0 1]
                     [0 5 0 0 0 6 0 9 0]
                     [0 0 9 0 6 0 0 0 0]
                     [5 3 0 7 0 0 0 0 8]
                     [0 8 0 0 2 0 0 3 9]]
                    40
                    3
                    
                    
                    cvp 1 Reply Last reply Reply Quote 0
                    • cvp
                      cvp @stephen last edited by

                      @stephen I don't know, up to @mibradoc to tell us more

                      1 Reply Last reply Reply Quote 0
                      • mibradoc
                        mibradoc last edited by

                        That 's correct, line 147 is still in the loop. But I 've commented lines 143 and 144 because the nameError and insert line 142 in order to debug. I don't need this print line in my script.
                        If you uncomment 143 and 144 and if the loop works fine, the name error would dissapear.
                        Wich version of Pythonista do you use? Mine is 3.3

                        cvp 1 Reply Last reply Reply Quote 0
                        • cvp
                          cvp @mibradoc last edited by

                          @mibradoc Pythonista 3.3 too
                          You need also to uncomment 146

                          1 Reply Last reply Reply Quote 0
                          • cvp
                            cvp last edited by

                            This

                            			for numero_carre in range ( (numcarre_altex // 3) * 3,((numcarre_altex//3)*3) + 3 ) :
                            				print ('x:',numero_carre) # BUG !!  sortie de la boucle for après le 1er passage !! 
                            				if numero_carre != numcarre_altex and key[0] not in carrint(numero_carre) :
                            					numero_carre_sans_chiffre = numero_carre
                            					
                            				colonnes_possibles=[]
                            				for colonne in range((numero_carre_sans_chiffre % 3)*3,(numero_carre_sans_chiffre % 3)*3 + 3) : 
                            

                            also crashes with

                            grille à résoudre ? libre
                            
                            [[1 4 0 0 7 0 9 2 0]
                             [3 0 0 0 0 2 8 5 4]
                             [0 0 0 0 5 0 6 0 7]
                             [0 0 0 2 0 0 0 7 0]
                             [9 0 6 0 0 0 4 0 1]
                             [0 5 0 0 0 6 0 0 0]
                             [0 0 9 0 6 0 0 0 0]
                             [5 3 0 7 0 0 0 0 8]
                             [0 8 0 0 2 0 0 3 9]]
                            50
                            (1, 1) [3, 4] 2
                            x: 0
                            Traceback (most recent call last):
                              File "/private/var/mobile/Containers/Shared/AppGroup/668A7D98-7216-47ED-917D-AA0B6173167E/Pythonista3/Documents/aa.py", line 147, in <module>
                                for colonne in range((numero_carre_sans_chiffre % 3)*3,(numero_carre_sans_chiffre % 3)*3 + 3) :
                            NameError: name 'numero_carre_sans_chiffre' is not defined
                            
                            1 Reply Last reply Reply Quote 0
                            • cvp
                              cvp last edited by cvp

                              Your loop on colonne uses numero_carre_sans_chiffre which is only defined in a if.

                              Are sure you don't need to indent more this loop?

                              				if numero_carre != numcarre_altex and key[0] not in carrint(numero_carre) :
                              					numero_carre_sans_chiffre = numero_carre
                              					
                              					colonnes_possibles=[]
                              					for colonne in range((numero_carre_sans_chiffre % 3)*3,(numero_carre_sans_chiffre % 3)*3 + 3) : 
                              
                              1 Reply Last reply Reply Quote 0
                              • mibradoc
                                mibradoc last edited by

                                @cvp you're right, but the bug remains on my iPad
                                It's strange that the same code runs without error on your device.
                                Thanks a lot to you and to @stephen

                                cvp 1 Reply Last reply Reply Quote 0
                                • cvp
                                  cvp @mibradoc last edited by

                                  @mibradoc As we have made some changes in your code to let it run without name error, I'm not sure we use exactly the same code.
                                  I also have an iPad (Mini 4) and I don't think comes from that.
                                  Could you post a code which runs without name error on your device but which stops after one loop

                                  1 Reply Last reply Reply Quote 0
                                  • stephen
                                    stephen last edited by

                                    pas de problème @mibradoc

                                    here is translated script incase anyone needed/wanted
                                    gist

                                    1 Reply Last reply Reply Quote 0
                                    • stephen
                                      stephen last edited by

                                      @cvp i beleive the error is the issue originaly. i say this only because it raises after one pass of for loop

                                      cvp 1 Reply Last reply Reply Quote 1
                                      • cvp
                                        cvp @stephen last edited by

                                        @stephen it is possible but as you have also changed some lines (comment, loop on colonne indentation), I just want to be sure that he and us try exactly the same code.

                                        1 Reply Last reply Reply Quote 0
                                        • mibradoc
                                          mibradoc last edited by

                                          The code on Dropbox stops after one loop. Whith a breakpoint on line 141 and then step by step you will see that the loop is executed only one time, not three as expected. The name error comes because the bypass over the lines 143 and 144 where the variable 'numero_carre_sans_chiffre' is assigned.

                                          cvp 1 Reply Last reply Reply Quote 0
                                          • cvp
                                            cvp @mibradoc last edited by

                                            @mibradoc yes, but as the name error occurs in the loop, it is normal the loop is stopped, isn'it?

                                            1 Reply Last reply Reply Quote 0
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