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Need to take a One Drive file and upload it to a FTP
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@cvp what a pity... in that case I’m have to do it manually forever.
Thanks for your help. :)
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@cvp I’ve found a post about the compatibility between OneDrive and Shortcuts but seems to be only for scan documents and related stuff nothing related to file routes.
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@Tito I had tried also a shortcut opening the url, without success.
Another solution could be perhaps web scraping on the OneDrive site...but surely not easy.
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@Tito I think I have found a solution.
You have to share (in OneDrive app or web page) your folder once and copy the generated link.Then, try this little script, where you have to replace my url with yours
import ui url = 'https://1drv.ms/u/s!AnAqP7kYeMWrgXwwda6qlAmt-bsl?e=wNu7Tb' w = ui.WebView() w.load_url(url) w.present()
You will get a web page where we will still have to find a way to press the download button to get a zip with all files in the folder.
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@Tito I'll (try to 🙄)do it this evening
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@Tito Finally, easier that I thought. For each OneDrive file that you need to upload, in the OneDrive app, once, you share it, and 'copy the link'. In the little script here under, you store in the files dict, the file name name and it's pasted link.
Even if the OneDrive file is modified, its link stays the same, at least during my tests.
The script downloads the OneDrive file and copies it locally.
The FTP unload part is another process, if you want help for it, ask me.Based on Generate OneDrive Direct-Download Link with C# or Python
import requests import base64 def create_onedrive_directdownload (onedrive_link): data_bytes64 = base64.b64encode(bytes(onedrive_link, 'utf-8')) data_bytes64_String = data_bytes64.decode('utf-8').replace('/','_').replace('+','-').rstrip("=") resultUrl = f"https://api.onedrive.com/v1.0/shares/u!{data_bytes64_String}/root/content" return resultUrl def main(): files = {'a.py':'https://1drv.ms/u/s!AnAqP7kYeMWrgX9L-9sMT08Fkgkf', 'aa.txt':'https://1drv.ms/t/s!AnAqP7kYeMWrggCb2Umu3Wn_Hr4G'} for nam_file in files: url_file = create_onedrive_directdownload(files[nam_file]) r = requests.get(url_file) with open(nam_file, mode='wb') as fil: fil.write(r.content) if __name__ == '__main__': main()
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@Tito including SFTP
import base64 import os import paramiko import requests import sys # https://towardsdatascience.com/how-to-get-onedrive-direct-download-link-ecb52a62fee4 def create_onedrive_directdownload (onedrive_link): data_bytes64 = base64.b64encode(bytes(onedrive_link, 'utf-8')) data_bytes64_String = data_bytes64.decode('utf-8').replace('/','_').replace('+','-').rstrip("=") resultUrl = f"https://api.onedrive.com/v1.0/shares/u!{data_bytes64_String}/root/content" return resultUrl def main(): path = sys.argv[0] i = path.rfind('/') path = path[:i+1] ip = 'my ip' user = 'user' pwd = 'password' try: sftp_port = 22 transport = paramiko.Transport((ip, sftp_port)) transport.connect(username=user, password=pwd) sftp = paramiko.SFTPClient.from_transport(transport) files = {'a.py':'https://1drv.ms/u/s!AnAqP7kYeMWrgX9L-9sMT08F', 'aa.txt':'https://1drv.ms/t/s!AnAqP7kYeMWrggCb2Umu3Wn_'} for nam_file in files: url_file = create_onedrive_directdownload(files[nam_file]) r = requests.get(url_file) with open(nam_file, mode='wb') as fil: fil.write(r.content) sftp.put(path + nam_file, nam_file) os.remove(nam_file) sftp.close() transport.close() except Exception as e: print(str(e)) if __name__ == '__main__': main()
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You could even find automatically the file name from its link
. . . for nam_file in files: r = requests.get(files[nam_file]) c = r.content.decode('utf-8') t = 'property="og:title" content="' i = c.find(t) if i >= 0: # <meta property="og:title" content="a.py"/> j = c.find('"/>',i) print(c[i+len(t):j]) url_file = create_onedrive_directdownload(files[nam_file]) . . .
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@cvp wow this is really awesome!!
Thanks so much, I will study your code and try to use it on my workflow.
Thanks again.
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for url in files.values(): text = requests.get(url).text tag = 'property="og:title" content="' _, _, content = text.partition(tag) if content: content, _, _ = content.partition('"/>') print(content) url_file = create_onedrive_directdownload(url)
... or maybe ...
from bs4 import BeautifulSoup
soup = BeautifulSoup(requests.get(url).content, 'html.parser')
content = soup.find("content").text -
@ccc I had tried with Eval_js on ui.WebView but there was a lot of "content" and other tries.
I'm sure there is a better analysis but my initial challenge was to get the links of the shared files. -
@ccc said:
for url in files.values():
I always forget this function. I'm sure that I become too old and that I'll have to find soon a new hobby 😢
Anyway, as usual, thanks for your advices. Even if I can't use them, other Python beginners will.
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Dude... I am 61 years old... No excuses... Keep pushing ;-)
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@ccc too late I just bought one
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@ccc said:
for url in files.values():
But later in the loop, I also use the files key (nam_file), thus...
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Hi, I’ve been trying but I think this is too complex for my skills.
You’ve been saying you were old guys, I’m felling useless at my almos brand new forties.
I don’t really understand how the function resolves the file and in my procedure I have to deal with an FTP server instead of an SFTP, so I don’t know where to touch the code and switching functions.
Many thanks for your help, and sorry for bothering, I’ll keep trying.
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What error messages are you seeing?
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@ccc thanks for answer and the link
I’m starting from here:
# coding: utf-8 import appex import console import os import ui from ftplib import FTP def main(): # Sharing: receive file fil = appex.get_file_path() if fil == None: print('no file passed') return server = 'address' user = 'account' pwd = 'pass' server_file = os.path.basename(fil) try: ftp = FTP(server) #connect ftp.encoding = 'utf-8' ftp.login(user,pwd) ipad_file = open(fil,'rb') ftp.storbinary('STOR '+server_file,ipad_file,blocksize=8192) ipad_file.close() ftp.close() except Exception as e: print(str(e)) appex.finish() if __name__ == '__main__': main()
With this code I take a file on OneDrive and upload it to a FTP server, but the code is made for taking files from iOS menu (I think that’s the appex part for the code structure).
Now here it comes the code that @cvp kindly searched and found it points to a web link route, it points to a file through an extracted link (is really awesome, black magic for me...).
As you can see, I’m not a coder, I tried to learn python, bought a book (Learn Python the Hard Way) but got jammed soon. And I have this problem with Pythonista when I search for info about python, the code is tailored for a computer environment, and making it work on Pythonista changes the game a lot.
Sorry I lost focus on this and I’m telling you my sorrows.
I tried to do it in parts first try to understand the code and make it run alone.
def create_onedrive_directdownload (onedrive_link): data_bytes64 = base64.b64encode(bytes(onedrive_link, 'utf-8')) data_bytes64_String = data_bytes64.decode('utf-8').replace('/','_').replace('+','-').rstrip("=") resultUrl = f"https://api.onedrive.com/v1.0/shares/u!{data_bytes64_String}/root/content" return resultUrl
I tried to put the OneDrive link on (onedrive_link) I thought it was the first position working as a shortcut but I got an “invalid syntax” error... I’ve noticed that my OneDrive links are not the same as the ones from the article (1drv vs my works personalised direction https:://xxxxxx-my.share point.com/:x:/g/personal/... maybe could be there the issue.
My next step would be to get the file and upload to the FTP address and after that try to make it work with two files and upload the together.
Thanks for your valuable help, I’m a mess with this and I’m trying, for me was a big win to understand the previous code for uploading files from iOS with the script. In the beginning I had to open an ftp app and navigate to the route every time I wanted to upload a file with this script I only have to check that everything worked smoothly, my goal was doing both things on a tap.
I’m asking myself, if I put a Pythonista script pointing to the files I have to upload in the OneDrive folder, would it found them? I suppose this shouldn’t need any route, only file names, am I right?