Python not wait for sub Function

cvp

@DavinE There are two base threads in Pythonista and you can force to run a process in The main_thread or in tHe ui one.
Remove this line and it is still not ok, put the line @on_main_thread

DavinE

@cvp like this:

@on_main_thread
def generatePDF(...)

and here:

def setFileNamePDF(self, customer, customer_project, materiallistType)

nothing ?

cvp

@DavinE Sincerely, I don't know but personally I would put the @on_main_thread before the other def.

DavinE

@cvp okay thanks i try it and response to you xD

DavinE

@cvp said:

@DavinE Sincerely, I don't know but personally I would put the @on_main_thread before the other def.

it works xD Thanks @cvp

cvp

@DavinE eureka

montykit

Hi everyone,

Is it possible to launch a python command without waiting for a return ? and therefore start the next command without waiting the previous one to finish ?

I searched and asked also on StackOverflow but so far I didn't found what I was looking for...

something that look promising might be the
1
concurrent.futures import ThreadPoolExecutor, ProcessPoolExecutor
as seen here -> https://stackoverflow.com/a/60832288/11943028

But this example is focus on results that I don't need. any ideas ?

Thank you.

https://fashionmentions.com/best-foundation/

DavinE

@montykit,

in my case @ui.in_backgroundworks... and don't wait for a return

maybe for you too

cvp

@montykit see the threading module, you could start one thread for each command

But what do you call a command?

cvp

@montykit try

import threading

class MyThread(threading.Thread):
	def __init__(self,cmd):
		threading.Thread.__init__(self)
		self.run = cmd

def cmd1():	
	s = 0
	for i in range(1000):
		s += 1
	print(s)
	
def cmd2():	
	s = 0
	for i in range(1000):
		s += i
	print(s)


MyThread(cmd1).start()
MyThread(cmd2).start()