• Karina

    Okay, thanks anyway

    posted in General Discussion read more
  • Karina

    Thank you a lot! And can you explain what happens in the two cases of if and elif?

    posted in General Discussion read more
  • Karina

    I'm trying to write tic-tac-toe on pythonista, so that 'O' will be in blue color and 'X' in red. The blue color works, but the red doesn't and I can't understand why. Here's my code
    Thank you very much for help

    import console
    
    x_o = [1,2,3,4,5,6,7,8,9]
    turn = ['X', 'O']
    
    class Color:
        def __init__(self, value):
            self.value = value
            self.red = 1
            self.green = 1
            self.blue = 1
            
        def switch_color(self):
            #all numbers will be white, 'X' - red, 'O' - blue
            if self.value == 'X':
                self.red, self.green, self.blue = 1, 0, 0
                print(self.__dict__)
            if self.value == 'O':
                self.red, self.green, self.blue = 0, 0, 1
            else:
                self.red, self.green, self.blue = 1, 1, 1
            console.set_color(self.red, self.green, self.blue)
        
        @classmethod    
        #asks where to put 'X'/'O' and replaces a number with it, making it an object of Color
        def putXO(cls, t):
            place = int(input(f'Where to put {t}? '))
            x_o[place-1] = cls(t)
                
    
    
    def to_Color(list):
        #makes all numbers in list to be Color objects
        for i in range(len(list)):
            list[i] = Color(list[i])
    
    def printXO(list):
        #makes the symbols to be printed in the color they need to be
        for num, i in enumerate(list,1):
            i.switch_color()
            if num%3 == 0:
                print(i.value)
            else:
                print(i.value, end='  ')
                
    to_Color(x_o)
    while x_o:
        for t in turn:
            Color.putXO(t)
            printXO(x_o)
    

    posted in General Discussion read more

Internal error.

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