• OkieWolf

    @cvp

    I think I understand now. But I can’t get the indentation at “return” to stop erroring.

    import math
    
    def triangle(short, long, hypotenuse, angle):
        if len([x for x in (hypotenuse, short, long, angle) if x]) != 2:
            raise ValueError("Exactly two parameters must be zero.")
        if hypotenuse and angle:
            angle = math.radians(angle)
            print   ('Short = ' + str(hypotenuse * (math.sin(angle))))
            print   ('Long = ' + str(hypotenuse * (math.cos(angle))))
        elif long and angle:
            angle = math.radians(angle)
            print   ('Short = ' + str(long * (math.tan(angle))))
            print   ('Hypotnuse = ' + str(long / (math.cos(angle))))
        elif short and angle:
            angle = math.radians(angle)
            print   ('Long = ' + str(short / (math.tan(angle))))
            print   ('Hypotnuse = ' + str(short / (math.sin(angle))))
        elif hypotenuse and short:
            print ('Long = ' + str(math.sqrt(hypotenuse ** 2 - short ** 2)))
            print ('Angle = ' + str(math.degrees(math.asin(short / hypotenuse))))
        elif hypotenuse and long:
            print ('Short = ' + str(math.sqrt(hypotenuse ** 2 - long ** 2)))
            print ('Angle = ' + str(math.degrees(math.acos(long / hypotenuse))))
        elif short and long:
            print ('Hypotenuse = ' + str(math.sqrt(short ** 2 + long ** 2)))
            print ('Angle = ' + str(math.degrees(math.atan(short / long))))
      return(short, long, hypotenuse, angle)
            
    #triangle(5,0,10,0) 
    

    posted in Pythonista read more
  • OkieWolf

    @cvp

    I still don’t know what you’re wanting. My code has many print calls.
    Adding return short, long, hypotenuse, angle where you have it above won’t do anything because it’s part of the last elif. If I add it in line with def Tringle it errors.

    import math
    
    def triangle(short, long, hypotenuse, angle):
        pass
        if len([x for x in (hypotenuse, short, long, angle) if x]) == 2:
            if hypotenuse and angle:
                angle = math.radians(angle)
                print   ('Short = ' + str(hypotenuse * (math.sin(angle))))
                print   ('Long = ' + str(hypotenuse * (math.cos(angle))))
            elif long and angle:
                angle = math.radians(angle)
                print   ('Short = ' + str(long * (math.tan(angle))))
                print   ('Hypotnuse = ' + str(long / (math.cos(angle))))
            elif short and angle:
                angle = math.radians(angle)
                print   ('Long = ' + str(short / (math.tan(angle))))
                print   ('Hypotnuse = ' + str(short / (math.sin(angle))))
            elif hypotenuse and short:
                print ('Long = ' + str(math.sqrt(hypotenuse ** 2 - short ** 2)))
                print ('Angle = ' + str(math.degrees(math.asin(short / hypotenuse))))
            elif hypotenuse and long:
                print ('Short = ' + str(math.sqrt(hypotenuse ** 2 - long ** 2)))
                print ('Angle = ' + str(math.degrees(math.acos(long / hypotenuse))))
            elif short and long:
                print ('Hypotenuse = ' + str(math.sqrt(short ** 2 + long ** 2)))
                print ('Angle = ' + str(math.degrees(math.atan(short / long))))
        else:
            print ("ERROR")
    
    triangle(5,0,10,0)  
    

    posted in Pythonista read more
  • OkieWolf

    @ccc

    I don’t understand step 2

    Step 2: change triangle() so it never prints but instead returns the answer with the statement return short, long, hypotenuse, angle.

    Are you wanting me to change....
    def triangle(short, long, hypotenuse, angle):

    Also, changing to print(triangle(5,0,10,0)) adds “none” after returned values

    posted in Pythonista read more
  • OkieWolf

    @ccc

    This will calculate any side or angle. But input still has to be zero for unknowns at input.

    import math
    
    def triangle(short, long, hypotenuse, angle):
        pass
        if len([x for x in (hypotenuse, short, long, angle) if x]) == 2:
            if hypotenuse and angle:
                angle = math.radians(angle)
                print   ('Short = ' + str(hypotenuse * (math.sin(angle))))
                print   ('Long = ' + str(hypotenuse * (math.cos(angle))))
            elif long and angle:
                angle = math.radians(angle)
                print   ('Short = ' + str(long * (math.tan(angle))))
                print   ('Hypotnuse = ' + str(long / (math.cos(angle))))
            elif short and angle:
                angle = math.radians(angle)
                print   ('Long = ' + str(short / (math.tan(angle))))
                print   ('Hypotnuse = ' + str(short / (math.sin(angle))))
            elif hypotenuse and short:
                print ('Long = ' + str(math.sqrt(hypotenuse ** 2 - short ** 2)))
                print ('Angle = ' + str(math.degrees(math.asin(short / hypotenuse))))
            elif hypotenuse and long:
                print ('Short = ' + str(math.sqrt(hypotenuse ** 2 - long ** 2)))
                print ('Angle = ' + str(math.degrees(math.acos(long / hypotenuse))))
            elif short and long:
                print ('Hypotenuse = ' + str(math.sqrt(short ** 2 + long ** 2)))
                print ('Angle = ' + str(math.degrees(math.atan(short / long))))
        else:
            print ("ERROR")
    
    triangle(5,0,10,0) 
    

    posted in Pythonista read more
  • OkieWolf

    @ccc

    Below will calculate short and long with given hypotenuse and angle but you have to enter zero for short and long input.

    import math
    
    def triangle(short, long, hypotenuse, angle):
        pass  
        if hypotenuse and angle:
            angle = math.radians(angle)
            print ('Short = ' + str(hypotenuse * (math.sin(angle))))
            print ('Long = ' + str(hypotenuse * (math.cos(angle))))
            
    triangle(0,0,10,30)
    

    posted in Pythonista read more
  • OkieWolf

    @ccc

    Please explain

    def triangle(a, b, hypotenuse=0, angle=45):
        pass  # math logic goes here
    Where triangle(3, 4) returns (3, 4, 5.0, 45)
    Where triangle(3, 0) would raise ValueError() 
    

    posted in Pythonista read more
  • OkieWolf

    Here’s what I came up with. It’s much shorter and easier to understand and I GREATLY appreciate all the help and patience.
    This version does all the other one did plus more. This version will calculate the other side and angle based on two sides input and can now calculate any side of the triangle based on angle and any one of the three sides.

    def button3_tapped(sender):
        hypotenuse = float(v['hypotenuse'].text or 0)
        short = float(v['short'].text or 0)
        long = float(v['long'].text or 0)
        angle = float(v['angle'].text or 0)
        if len([x for x in (hypotenuse, short, long, angle) if x]) != 2:
            v['mess'].text = "Enter two fields"
            v['mess'].background_color = 'red'
            v['mess'].text_color = 'white'
            return
        if hypotenuse and not angle:
            if short and not long:
                v['long'].text = str(math.sqrt(hypotenuse ** 2 - short ** 2))
                v['long'].text_color = 'green'
                v['angle'].text = str(math.degrees(math.asin(short / hypotenuse)))
                v['angle'].text_color = 'green'
            elif long and not short:
                v['short'].text = str(math.sqrt(hypotenuse ** 2 - long ** 2))
                v['short'].text_color = 'green'
                v['angle'].text = str(math.degrees(math.acos(long / hypotenuse)))
                v['angle'].text_color = 'green'
        else:
            if not angle:
                v['hypotenuse'].text = str(math.sqrt(short ** 2 + long ** 2))
                v['hypotenuse'].text_color = 'green'
                v['angle'].text = str(math.degrees(math.atan(short / long)))
                v['angle'].text_color = 'green'
            
        if angle:
            angle = math.radians(angle)
            if short and not long and not hypotenuse:
                v['hypotenuse'].text = str(short / (math.sin(angle)))
                v['hypotenuse'].text_color = 'green'
                v['long'].text = str(short / (math.tan(angle)))
                v['long'].text_color = 'green'
            elif long and not short and not hypotenuse:
                v['hypotenuse'].text = str(long / (math.cos(angle)))
                v['hypotenuse'].text_color = 'green'
                v['short'].text = str(long * (math.tan(angle)))
                v['short'].text_color = 'green'
            elif angle and hypotenuse and not long and not short:
                v['short'].text = str(hypotenuse * (math.sin(angle)))
                v['short'].text_color = 'green'
                v['long'].text = str(hypotenuse * (math.cos(angle)))
                v['long'].text_color = 'green' 
    

    posted in Pythonista read more
  • OkieWolf

    Agreed. It works fine if short and long are the same number, which equals 45 degrees.

    posted in Pythonista read more
  • OkieWolf

    @ccc

    I’m attempting to rewrite my code to be more efficient and am utilizing a couple of code snippets that a couple of you have supplied. However, in the below code I noticed that the output is 0.0 if both inputs happen to be the same number. I’m not understanding why.

    def button3_tapped(sender):
        hypotenuse = float(v['hypotenuse'].text or 0)
        short = float(v['short'].text or 0)
        long = float(v['long'].text or 0)
        if len([x for x in (hypotenuse, short, long) if x]) != 2:
            v['mess'].text = "Enter two fields"
            v['mess'].background_color = 'red'
            v['mess'].text_color = 'white'
            return
        if hypotenuse:
            if short and not long:
                v['long'].text = str(math.sqrt(hypotenuse ** 2 - short ** 2))
                v['long'].text_color = 'green'
            elif long and not short:
                v['short'].text = str(math.sqrt(hypotenuse ** 2 - long ** 2))
                v['short'].text_color = 'green'
        else:
            v['hypotenuse'].text = str(math.sqrt(short ** 2 + long ** 2))
            v['hypotenuse'].text_color = 'green' ```

    posted in Pythonista read more

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