• OkieWolf

@cvp

I think I understand now. But I can’t get the indentation at “return” to stop erroring.

``````import math

def triangle(short, long, hypotenuse, angle):
if len([x for x in (hypotenuse, short, long, angle) if x]) != 2:
raise ValueError("Exactly two parameters must be zero.")
if hypotenuse and angle:
print   ('Short = ' + str(hypotenuse * (math.sin(angle))))
print   ('Long = ' + str(hypotenuse * (math.cos(angle))))
elif long and angle:
print   ('Short = ' + str(long * (math.tan(angle))))
print   ('Hypotnuse = ' + str(long / (math.cos(angle))))
elif short and angle:
print   ('Long = ' + str(short / (math.tan(angle))))
print   ('Hypotnuse = ' + str(short / (math.sin(angle))))
elif hypotenuse and short:
print ('Long = ' + str(math.sqrt(hypotenuse ** 2 - short ** 2)))
print ('Angle = ' + str(math.degrees(math.asin(short / hypotenuse))))
elif hypotenuse and long:
print ('Short = ' + str(math.sqrt(hypotenuse ** 2 - long ** 2)))
print ('Angle = ' + str(math.degrees(math.acos(long / hypotenuse))))
elif short and long:
print ('Hypotenuse = ' + str(math.sqrt(short ** 2 + long ** 2)))
print ('Angle = ' + str(math.degrees(math.atan(short / long))))
return(short, long, hypotenuse, angle)

#triangle(5,0,10,0)
``````

• OkieWolf

@cvp

I still don’t know what you’re wanting. My code has many print calls.
Adding return short, long, hypotenuse, angle where you have it above won’t do anything because it’s part of the last elif. If I add it in line with def Tringle it errors.

``````import math

def triangle(short, long, hypotenuse, angle):
pass
if len([x for x in (hypotenuse, short, long, angle) if x]) == 2:
if hypotenuse and angle:
print   ('Short = ' + str(hypotenuse * (math.sin(angle))))
print   ('Long = ' + str(hypotenuse * (math.cos(angle))))
elif long and angle:
print   ('Short = ' + str(long * (math.tan(angle))))
print   ('Hypotnuse = ' + str(long / (math.cos(angle))))
elif short and angle:
print   ('Long = ' + str(short / (math.tan(angle))))
print   ('Hypotnuse = ' + str(short / (math.sin(angle))))
elif hypotenuse and short:
print ('Long = ' + str(math.sqrt(hypotenuse ** 2 - short ** 2)))
print ('Angle = ' + str(math.degrees(math.asin(short / hypotenuse))))
elif hypotenuse and long:
print ('Short = ' + str(math.sqrt(hypotenuse ** 2 - long ** 2)))
print ('Angle = ' + str(math.degrees(math.acos(long / hypotenuse))))
elif short and long:
print ('Hypotenuse = ' + str(math.sqrt(short ** 2 + long ** 2)))
print ('Angle = ' + str(math.degrees(math.atan(short / long))))
else:
print ("ERROR")

triangle(5,0,10,0)
``````

• OkieWolf

@ccc

I don’t understand step 2

Step 2: change triangle() so it never prints but instead returns the answer with the statement return short, long, hypotenuse, angle.

Are you wanting me to change....
def triangle(short, long, hypotenuse, angle):

Also, changing to print(triangle(5,0,10,0)) adds “none” after returned values

• OkieWolf

@ccc

This will calculate any side or angle. But input still has to be zero for unknowns at input.

``````import math

def triangle(short, long, hypotenuse, angle):
pass
if len([x for x in (hypotenuse, short, long, angle) if x]) == 2:
if hypotenuse and angle:
print   ('Short = ' + str(hypotenuse * (math.sin(angle))))
print   ('Long = ' + str(hypotenuse * (math.cos(angle))))
elif long and angle:
print   ('Short = ' + str(long * (math.tan(angle))))
print   ('Hypotnuse = ' + str(long / (math.cos(angle))))
elif short and angle:
print   ('Long = ' + str(short / (math.tan(angle))))
print   ('Hypotnuse = ' + str(short / (math.sin(angle))))
elif hypotenuse and short:
print ('Long = ' + str(math.sqrt(hypotenuse ** 2 - short ** 2)))
print ('Angle = ' + str(math.degrees(math.asin(short / hypotenuse))))
elif hypotenuse and long:
print ('Short = ' + str(math.sqrt(hypotenuse ** 2 - long ** 2)))
print ('Angle = ' + str(math.degrees(math.acos(long / hypotenuse))))
elif short and long:
print ('Hypotenuse = ' + str(math.sqrt(short ** 2 + long ** 2)))
print ('Angle = ' + str(math.degrees(math.atan(short / long))))
else:
print ("ERROR")

triangle(5,0,10,0)
``````

• OkieWolf

@ccc

Below will calculate short and long with given hypotenuse and angle but you have to enter zero for short and long input.

``````import math

def triangle(short, long, hypotenuse, angle):
pass
if hypotenuse and angle:
print ('Short = ' + str(hypotenuse * (math.sin(angle))))
print ('Long = ' + str(hypotenuse * (math.cos(angle))))

triangle(0,0,10,30)
``````

• OkieWolf

@ccc

``````def triangle(a, b, hypotenuse=0, angle=45):
pass  # math logic goes here
Where triangle(3, 4) returns (3, 4, 5.0, 45)
Where triangle(3, 0) would raise ValueError()
``````

• OkieWolf

Here’s what I came up with. It’s much shorter and easier to understand and I GREATLY appreciate all the help and patience.
This version does all the other one did plus more. This version will calculate the other side and angle based on two sides input and can now calculate any side of the triangle based on angle and any one of the three sides.

``````def button3_tapped(sender):
hypotenuse = float(v['hypotenuse'].text or 0)
short = float(v['short'].text or 0)
long = float(v['long'].text or 0)
angle = float(v['angle'].text or 0)
if len([x for x in (hypotenuse, short, long, angle) if x]) != 2:
v['mess'].text = "Enter two fields"
v['mess'].background_color = 'red'
v['mess'].text_color = 'white'
return
if hypotenuse and not angle:
if short and not long:
v['long'].text = str(math.sqrt(hypotenuse ** 2 - short ** 2))
v['long'].text_color = 'green'
v['angle'].text = str(math.degrees(math.asin(short / hypotenuse)))
v['angle'].text_color = 'green'
elif long and not short:
v['short'].text = str(math.sqrt(hypotenuse ** 2 - long ** 2))
v['short'].text_color = 'green'
v['angle'].text = str(math.degrees(math.acos(long / hypotenuse)))
v['angle'].text_color = 'green'
else:
if not angle:
v['hypotenuse'].text = str(math.sqrt(short ** 2 + long ** 2))
v['hypotenuse'].text_color = 'green'
v['angle'].text = str(math.degrees(math.atan(short / long)))
v['angle'].text_color = 'green'

if angle:
if short and not long and not hypotenuse:
v['hypotenuse'].text = str(short / (math.sin(angle)))
v['hypotenuse'].text_color = 'green'
v['long'].text = str(short / (math.tan(angle)))
v['long'].text_color = 'green'
elif long and not short and not hypotenuse:
v['hypotenuse'].text = str(long / (math.cos(angle)))
v['hypotenuse'].text_color = 'green'
v['short'].text = str(long * (math.tan(angle)))
v['short'].text_color = 'green'
elif angle and hypotenuse and not long and not short:
v['short'].text = str(hypotenuse * (math.sin(angle)))
v['short'].text_color = 'green'
v['long'].text = str(hypotenuse * (math.cos(angle)))
v['long'].text_color = 'green'
``````

• OkieWolf

@ccc

I’m attempting to rewrite my code to be more efficient and am utilizing a couple of code snippets that a couple of you have supplied. However, in the below code I noticed that the output is 0.0 if both inputs happen to be the same number. I’m not understanding why.

``````def button3_tapped(sender):
hypotenuse = float(v['hypotenuse'].text or 0)
short = float(v['short'].text or 0)
long = float(v['long'].text or 0)
if len([x for x in (hypotenuse, short, long) if x]) != 2:
v['mess'].text = "Enter two fields"
v['mess'].background_color = 'red'
v['mess'].text_color = 'white'
return
if hypotenuse:
if short and not long:
v['long'].text = str(math.sqrt(hypotenuse ** 2 - short ** 2))
v['long'].text_color = 'green'
elif long and not short:
v['short'].text = str(math.sqrt(hypotenuse ** 2 - long ** 2))
v['short'].text_color = 'green'
else:
v['hypotenuse'].text = str(math.sqrt(short ** 2 + long ** 2))
v['hypotenuse'].text_color = 'green' `````````