List = dictionary

[AZOM]

I’m searching for a way to see if the numbers in a list = the numbers in a dictionary key. EX: dictionary = {12345:6, 01928:7} list = [1, 2, 3]. And the output would be like: the list fit in the key 12345.

[cvp]

@AZOM not nice, I agree

dict = {'12345':6, '01928':7}
list = [1, 2, 3]

for k in dict.keys():
	ok = True
	for e in list:
		if str(e) not in k:
			ok = False
			break
	if ok:
		print('list in',k)
		break 

[cvp]

Better

dict = {'12345':6, '1928':7}
lst = [1, 2, 3]

for k in dict.keys():
	if  [x for x in lst if str(x) in k] == lst:
		print('lst in',k)
		break 

[pulbrich]

dict = {'12345':6, '01928':7}
list = [1, 2, 3]
set_list = set(list)

found = []
for k in dict.keys():
  if set([int(aK) for aK in k]) >= set_list:
    found.append(k)
    
print(found) 

[pulbrich]

Or, if readability is not much of a concern:

dict = {'12345':6, '01928':7}
list = [1, 2, 3]

found = [k for k in dict.keys() if set([int(aK) for aK in k]) >= set(list)]
print(found) 

[cvp]

@pulbrich I like it.

[ccc]

You almost never need to use dict.keys().

dct = {"12345": 6, "01928": 7}
lst = [1, 2, 3, 12, 34, 234]
print("\n".join(key for key in dct if all(str(i) in key for i in lst)))

[AZOM]

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