• BarryZ

    @cvp Thanks! You have already helped me a lot! I will search it on the internet to figure it out.

    posted in Pythonista read more
  • BarryZ

    @cvp Besides, when I code like this:
    class quadratic_functions:
    def qfx(self,y,a,b,c):
    delta=b2-4a(c-y)
    if delta==0:
    x=-b/2a
    print('the x is',x)
    if delta<0:
    print('there is no solution for x.')
    else:
    x1=x=(-b+delta
    (1/2))/(2a)
    x2=x=(-b-delta**(1/2))/(2*a)
    print('x1 is',x1)
    print('x2 is',x2)

    When I run it on my Mac and pythonista3:

    q=quadratic_functions()
    q.qfx(1,4,8,10)
    there is no solution for x.

    It works.

    Or when I code like this:
    class quadratic_functions:
    def qfx(y,a,b,c):
    delta=b2-4a(c-y)
    if delta==0:
    x=-b/2a
    print('the x is',x)
    if delta<0:
    print('there is no solution for x.')
    else:
    x1=x=(-b+delta
    (1/2))/(2a)
    x2=x=(-b-delta**(1/2))/(2*a)
    print('x1 is',x1)
    print('x2 is',x2)

    When I run it on my Mac and pythonista3:

    q=quadratic_functions
    q.qfx(1,4,8,10)
    there is no solution for x

    It works.

    posted in Pythonista read more
  • BarryZ

    @cvp There is no @staticmethod.

    On my Mac:

    class Quadratic_Functions_4_1:
    def QFY(x,a,b,c):
    y=ax2+bx+c
    print('the y is',y)

    Run on my Mac:

    Q=Quadratic_Funtions_4_1()
    Q.QFY(1,4,8,10)
    the y is 22

    posted in Pythonista read more
  • BarryZ

    @cvp Thanks!

    posted in Pythonista read more
  • BarryZ

    @dgelessus Thanks for your suggestions. yeah, I am sure. On my Mac, I use python 3.7.x to code. I don’t know why.

    posted in Pythonista read more
  • BarryZ

    @cvp Thanks! It works! I am a beginner of python. Could you tell me why there must be self? When I code on my Mac, it could run without self, but when I code in pythonista3 on my phone, it must run with writing self.why? Look forward to your replying.

    posted in Pythonista read more
  • BarryZ

    The problem is when I code on my Mac, the codes can run. However, when I use the same code script in the pythonista 3, it can not run, which said that something takes n positional arguments, but n+1 were given.
    I don not know whether this is the bug in pythonista3 or not?

    class Quadratic_Functions_4_1:

    def QFY(x,a,b,c):
        y=a*x**2+b*x+c
        print('the y is',y)
    
    def QFX(y,a,b,c):
        delta=b**2-4*a*(c-y)
        if delta<0:
            print('the function does not exist.')
        if delta==0:
            x=-b/2
            print('the x is',x)
        else:
            x1=x=(-b+(delta**(1/2)))/(2*a)
            x2=x=(-b-(delta**(1/2)))/(2*a)
            print('x1 is',x1)
            print('x2 is',x2)
    
    def QFA(x,y,b,c):
        if x==0:
            print('the function is a line:')
        else:
            a=(y-b*x-c)/x**2
            print('the a is',a)
    
    def QFB(x,y,a,c):
        if x==0:
            print('the function is a line:')
        else:
            b=(y-a*x**2-c)/x
            print('the b is',b)
    
    def QFC(x,y,a,b):
        c=y-a*x**2-b*x
        print('the c is',c)
    

    When I ran this code in pythonista3, I received the following sentences:

    q=Quadratic_Functions_4_1()
    q.QFY(1,2,3,4)
    Traceback (most recent call last):
    File "<string>", line 1, in <module>
    TypeError: QFY() takes 4 positional arguments but 5 were given

    posted in Pythonista read more

Internal error.

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