
BarryZ
@cvp Thanks! You have already helped me a lot! I will search it on the internet to figure it out.

BarryZ
@cvp Besides, when I code like this:
class quadratic_functions:
def qfx(self,y,a,b,c):
delta=b24a(cy)
if delta==0:
x=b/2a
print('the x is',x)
if delta<0:
print('there is no solution for x.')
else:
x1=x=(b+delta(1/2))/(2a)
x2=x=(bdelta**(1/2))/(2*a)
print('x1 is',x1)
print('x2 is',x2)When I run it on my Mac and pythonista3:
q=quadratic_functions()
q.qfx(1,4,8,10)
there is no solution for x.It works.
Or when I code like this:
class quadratic_functions:
def qfx(y,a,b,c):
delta=b24a(cy)
if delta==0:
x=b/2a
print('the x is',x)
if delta<0:
print('there is no solution for x.')
else:
x1=x=(b+delta(1/2))/(2a)
x2=x=(bdelta**(1/2))/(2*a)
print('x1 is',x1)
print('x2 is',x2)When I run it on my Mac and pythonista3:
q=quadratic_functions
q.qfx(1,4,8,10)
there is no solution for xIt works.

BarryZ
@cvp There is no @staticmethod.
On my Mac:
class Quadratic_Functions_4_1:
def QFY(x,a,b,c):
y=ax2+bx+c
print('the y is',y)Run on my Mac:
Q=Quadratic_Funtions_4_1()
Q.QFY(1,4,8,10)
the y is 22 

BarryZ
@dgelessus Thanks for your suggestions. yeah, I am sure. On my Mac, I use python 3.7.x to code. I don’t know why.

BarryZ
@cvp Thanks! It works! I am a beginner of python. Could you tell me why there must be self? When I code on my Mac, it could run without self, but when I code in pythonista3 on my phone, it must run with writing self.why? Look forward to your replying.

BarryZ
The problem is when I code on my Mac, the codes can run. However, when I use the same code script in the pythonista 3, it can not run, which said that something takes n positional arguments, but n+1 were given.
I don not know whether this is the bug in pythonista3 or not?class Quadratic_Functions_4_1:
def QFY(x,a,b,c): y=a*x**2+b*x+c print('the y is',y) def QFX(y,a,b,c): delta=b**24*a*(cy) if delta<0: print('the function does not exist.') if delta==0: x=b/2 print('the x is',x) else: x1=x=(b+(delta**(1/2)))/(2*a) x2=x=(b(delta**(1/2)))/(2*a) print('x1 is',x1) print('x2 is',x2) def QFA(x,y,b,c): if x==0: print('the function is a line:') else: a=(yb*xc)/x**2 print('the a is',a) def QFB(x,y,a,c): if x==0: print('the function is a line:') else: b=(ya*x**2c)/x print('the b is',b) def QFC(x,y,a,b): c=ya*x**2b*x print('the c is',c)
When I ran this code in pythonista3, I received the following sentences:
q=Quadratic_Functions_4_1()
q.QFY(1,2,3,4)
Traceback (most recent call last):
File "<string>", line 1, in <module>
TypeError: QFY() takes 4 positional arguments but 5 were given