@mikael
Max - variable count to, for example 100.
So i need count quantity uniques examples for some mathematic operator, in my case '+' or '-'
I can't have example 98+10 or 25-50
Max example result must be under 100 or equal
Minimum example result must be under 0

Hello pythonista community. Can someone adwise me formula for recognize quantity of unique combinations when you count to some max digit with sign "-" (minus)? Answer can't be under zero.

Example1:
sign = '-'
max = 2
2-2
2-1
1-1

• we have only three unique combinations.

Example2:
answer can't be upper max:
max = 2
1+1

• we have only one unique example.

I already have formula for two signs "+-": unic_col=max**2

But i need formula for '+' and '-'
And maybe someone know for:
+-×
+-/
+-×/
/×

So, i need function like that:

def uniques_col(operators, max):
if operators == '+-':
return max**2
elif operators == '+':
return .....
elif operators == '-':
return .....
elif operators == '+-×':
return .....
......

I install last version pandas over stash
Then i test with some code:

import pandas as pd
df = pd.DataFrame({'id':range(15), 'chars': ['ab']*15})
print(df)

After run i receive
this version of pandas is incompatible with numpy 1.13.3

How to fix, maybe, anybody know?

+1..........

@cvp thank's a lot. It working for '+', '-' and '+-':

def uniques_col(operators, max):
    col = 0
    if operators == '+':
        for i in range(1,max):
            for j in range(1,max-i+1):
                col += 1
    elif operators == '-':
        for i in range(1,max+1):
            for j in range(1,i+1):
                col += 1
    elif operators == '+-':
            col = max**2
    
    return col
    

while True:
    op = input('operator\n')
    max = int(input('max\n'))
    print(uniques_col(op,max))

And maybe you know uniques col for:
+-×
+-/
+-×/
/×

??? Thank's in advance!!!

@cvp in iOS settings/speech i hear sound when i change speed (Turtle)

@cvp, thank you all for help!!!
With your function i receive right col for '-', but not for '+':

def uniques_col(operators, max):
n = 0
if operators == '+':
for i in range(1,max):
for j in range(i,max-i+1):
n += 1
print(i,operators,j,'=',i+j)
elif operators == '-':
for i in range(1,max+1):
for j in range(1,i+1):
n += 1
print(i,operators,j,'=',i-j)
return n

while True:
op = input('operator\n')
max = int(input('max\n'))
print(uniques_col(op,max))

What i receive:
operator-
max4
1 - 1 = 0
2 - 1 = 1
2 - 2 = 0
3 - 1 = 2
3 - 2 = 1
3 - 3 = 0
4 - 1 = 3
4 - 2 = 2
4 - 3 = 1
4 - 4 = 0
10
operator+
max4
1 + 1 = 2
1 + 2 = 3
1 + 3 = 4
2 + 2 = 4
4

Where is 1+3 and 2+1, so for '+' i need receive 6 unique examples.

@JonB i have two same 3rd generation ipads, run the same program and have voice in one of them and not in another one. Yes, voice is on ))) in settings. And i have not errors.

@mikael
Max - variable count to, for example 100.
So i need count quantity uniques examples for some mathematic operator, in my case '+' or '-'
I can't have example 98+10 or 25-50
Max example result must be under 100 or equal
Minimum example result must be under 0

Hello pythonista community. Can someone adwise me formula for recognize quantity of unique combinations when you count to some max digit with sign "-" (minus)? Answer can't be under zero.

Example1:
sign = '-'
max = 2
2-2
2-1
1-1

• we have only three unique combinations.

Example2:
answer can't be upper max:
max = 2
1+1

• we have only one unique example.

I already have formula for two signs "+-": unic_col=max**2

But i need formula for '+' and '-'
And maybe someone know for:
+-×
+-/
+-×/
/×

So, i need function like that:

def uniques_col(operators, max):
if operators == '+-':
return max**2
elif operators == '+':
return .....
elif operators == '-':
return .....
elif operators == '+-×':
return .....
......

@cvp
get an error module 'speech' (built-in)> is a built-in module

@sulcud fresh install doesn't helped. I was delete speech module before over stash(((. Now i can't recover.